# 从尾到头打印链表(剑指Offer 06)

# 题目

输入一个链表的头节点,从尾到头反过来返回每个节点的值(用数组返回)。

# 示例

输入:head = [1,3,2] 输出:[2,3,1]

# 限制

  • 0 <= 链表长度 <= 10000

# 算法

# reverse()

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
export const reversePrint = (head) => {
	const arr = [];
	while (head) {
		arr.push(head.val);
		head = head.next;
	}
	return arr.reverse();
};
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# 递归

注意push()返回的是操作后数组的长度length,不能直接return

/**
 * Definition for singly-linked list.
 * function ListNode(val) {
 *     this.val = val;
 *     this.next = null;
 * }
 */
export const reversePrint = (head) => {
	if (!head) return [];
	let arr = reversePrint(head.next);
	arr.push(head.val);
	return arr;
};
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